The rate constant of a second order reaction is 2.5x10^-3 L mol^-1 s^-1. Expressed in m^3 mol^-1 min^-1 (use 1 L = 10^-3 m^3) it is

JEE Main levelSingle correct optionDifficulty 2 of 3ck071

The rate constant of a second order reaction is $2.5 \times 1 0^{- 3} L mo l^{- 1} s^{- 1}$ . Expressed in $m^{3} mo l^{- 1} mi n^{- 1}$ (use $1 L = 1 0^{- 3} m^{3}$ ) it is

1 L = 1 0^{- 3} m^{3}

and

1 min = 60 s

, so one reciprocal second becomes 60 reciprocal minutes. Thus

k = 2.5 \times 1 0^{- 3} \times 1 0^{- 3} \times 60 = 1.5 \times 1 0^{- 4} m^{3} mo l^{- 1} mi n^{- 1}