Numerical answer type, answer in 10^-4 M min^-1, tolerance 0.02.
Answer: 7.0711 10^-4 M min^-1
For first order, rate =k[A], so the rate decays with the same half-life as the concentration (here k=0.693/60=0.01155 min−1, [A]0=0.346 M). Since 150/60=2.5 half-lives, rate =4.0×10−3×(1/2)2.5=4.0×10−3×0.17678=7.07×10−4 M min−1.