JEE Advanced levelSingle correct optionDifficulty 3 of 3ck026
For a reaction with rate =k[A]n the initial rate is 6.4×10−3Ms−1 at [A]=0.50M and 8.0×10−4Ms−1 at [A]=0.125M. The initial rate at [A]=0.0625M is
A2.83×10−4Ms−1
B8.00×10−4Ms−1
C1.00×10−4Ms−1
D2.26×10−3Ms−1
Answer: A
The concentration falls by 4 and the rate by 8, so 4n=8 and n=1.5. Going from 0.50 M to 0.0625 M is a fall by a factor 8, so the rate falls by 81.5=22.63: 6.4×10−3/22.63=2.83×10−4Ms−1.