Four initial-rate experiments for A + B + C -> P gave: ([A], [B], [C] in M; rate in M s^-1) (1) 0.10, 0.10, 0.20, 1.50x10^-3; (2) 0.20, 0.10, 0.20, 3.00x10^-3; (3) 0.10, 0.30, 0.20, 1.35x10^-2; (4) 0.10, 0.10, 0.60, 1.50x10^-3. The initial rate for [A] = 0.40, [B] = 0.20, [C] = 0.10 M is

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JEE Advanced levelSingle correct optionDifficulty 3 of 3ck023

Four initial-rate experiments for $A + B + C P$ gave: ( $[A], [B], [C]$ in M; rate in $M s^{- 1}$ ) (1) 0.10, 0.10, 0.20, $1.50 \times 1 0^{- 3}$ ; (2) 0.20, 0.10, 0.20, $3.00 \times 1 0^{- 3}$ ; (3) 0.10, 0.30, 0.20, $1.35 \times 1 0^{- 2}$ ; (4) 0.10, 0.10, 0.60, $1.50 \times 1 0^{- 3}$ . The initial rate for $[A] = 0.40$ , $[B] = 0.20$ , $[C] = 0.10 M$ is

A $2.40 \times 1 0^{- 2} M s^{- 1}$
B $1.20 \times 1 0^{- 2} M s^{- 1}$
C $4.80 \times 1 0^{- 2} M s^{- 1}$
D $6.00 \times 1 0^{- 3} M s^{- 1}$

Answer: A

(1)->(2): A doubled, rate x2, so first order in A. (1)->(3): B tripled, rate x9, so second order in B. (1)->(4): C tripled, rate unchanged, so zero order in C. Then

k = 1.50 \times 1 0^{- 3} / (0.10 \times 0.1 0^{2}) = 1.5

, and the new rate

= 1.5 \times 0.40 \times 0.2 0^{2} = 2.40 \times 1 0^{- 2} M s^{- 1}

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Four initial-rate experiments for A+B+C​P gave: ([A],[B],[C] in M; rate in M s−1) (1) 0.10, 0.10, 0.20, 1.50×10−3; (2) 0.20, 0.10, 0.20, 3.00×10−3; (3) 0.10, 0.30, 0.20, 1.35×10−2; (4) 0.10, 0.10, 0.60, 1.50×10−3. The initial rate for [A]=0.40, [B]=0.20, [C]=0.10 M is

Answer: A

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