The rate constant of a second order reaction is 2.7x10^-3 L mol^-1 s^-1. Express it in 10^-3 m^3 mol^-1 h^-1 (use 1 L = 10^-3 m^3; two decimals).

JEE Main levelNumerical answerDifficulty 2 of 3ck019

The rate constant of a second order reaction is $2.7 \times 1 0^{- 3} L mo l^{- 1} s^{- 1}$ . Express it in $1 0^{- 3} m^{3} mo l^{- 1} h^{- 1}$ (use $1 L = 1 0^{- 3} m^{3}$ ; two decimals).

Numerical answer type, answer in 10^-3 m^3 mol^-1 h^-1, tolerance 0.02.

Convert litres to cubic metres by multiplying by

1 0^{- 3}

and seconds to hours by multiplying by

3600

(since

k

has

s^{- 1}

, one hour contains 3600 s). So

k = 2.7 \times 1 0^{- 3} \times 1 0^{- 3} \times 3600 = 0.00972

, i.e.

9.72 \times 1 0^{- 3} m^{3} mo l^{- 1} h^{- 1}