JEE Main levelSingle correct optionDifficulty 2 of 3ck015
For A+Bproducts the proposed mechanism is: step 1, A+BC (fast, equilibrium); step 2, C+Aproducts (slow). The rate law consistent with this mechanism is
Arate =k[A]2[B]
Brate =k[A][B]
Crate =k[C]
Drate =k[A][B]2
Answer: A
The slow step fixes the rate: rate =k2[C][A]. The intermediate C is removed using the fast equilibrium [C]=K[A][B]. Therefore rate =k2K[A]2[B]=k[A]2[B], third order overall.