NH4Cl(g) NH3(g) + HCl(g) has a calculated vapour density of 26.75 for undissociated NH4Cl (molar mass 53.5 g/mol). If dissociation is complete, the vapour density of the gas mixture is

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$NH X_{4} Cl (g) NH X_{3} (g) + HCl (g)$ has a calculated vapour density of $26.75$ for undissociated $NH X_{4} Cl$ (molar mass $53.5 g/mol$ ). If dissociation is complete, the vapour density of the gas mixture is

Complete dissociation doubles the number of moles (

1 + α = 2

), so the vapour density halves:

26.75/2 = 13.375