Answer: B, C
K falls as T rises, so the reaction is exothermic and statement A is false. From the first two data points, ΔH∘=Rln(K400/K300)/(1/300−1/400)=−60.0 kJ mol−1, and the last two give -60.0, so B is true. Extrapolating from 500 K with this ΔH∘ gives K600≈1.00, so C is true. Finally ΔS∘=(ΔH∘+RTlnK)/T at 400 K is -100 J/(mol K), negative, so D is false.