For 2NO(g) + O2(g) 2NO2(g), K_c = 2.0x10^3 L mol^-1 at 500 K. Using R = 0.0821 L atm mol^-1 K^-1 and 1 atm = 101.3 kPa, K_p in kPa^-1 is

JEE Advanced levelSingle correct optionDifficulty 3 of 3ce098

For $2 NO (g) + O X_{2} (g) 2 NO X_{2} (g)$ , $K_{c} = 2.0 \times 1 0^{3} L mo l^{- 1}$ at 500 K. Using $R = 0.0821 L atm mo l^{- 1} K^{- 1}$ and $1 atm = 101.3 kPa$ , $K_{p}$ in $kP a^{- 1}$ is

Δ n = - 1

, so

K_{p} = K_{c} / RT = 2000/41.05 = 48.72 at m^{- 1}

. Since

1 at m^{- 1} = 1/101.3 kP a^{- 1}

K_{p} = 48.72/101.3 = 0.481 kP a^{- 1}