Solid NH4HS is placed in an evacuated flask and decomposes: NH4HS(s) NH3(g) + H2S(g). At equilibrium the total pressure is 0.90 atm. Calculate K_p in atm^2, correct to two decimal places.

JEE Main levelNumerical answerDifficulty 2 of 3ce079

Solid $NH X_{4} HS$ is placed in an evacuated flask and decomposes: $NH X_{4} HS (s) NH X_{3} (g) + H X_{2} S (g)$ . At equilibrium the total pressure is 0.90 atm. Calculate $K_{p}$ in $at m^{2}$ , correct to two decimal places.

Numerical answer type, answer in atm^2, tolerance 0.01.

The gases are formed in a 1:1 ratio, so

p_{NH X_{3}} = p_{H X_{2} S} = 0.90/2 = 0.45

atm.

K_{p} = 0.45 \times 0.45 = 0.2025 at m^{2}