JEE Main levelSingle correct optionDifficulty 2 of 3ce025
At equilibrium in a rigid vessel, [PClX5]=0.20M, [PClX3]=0.10M and [ClX2]=0.10M for PClX5(g)PClX3(g)+ClX2(g). Then 0.10 mol/L of ClX2 is injected at constant temperature. Immediately after the addition, Qc and the direction of the net reaction are
AQc=0.10, backward
BQc=0.10, forward
CQc=0.067, backward
DQc=0.05, no net change
Answer: A
First Kc=(0.10)(0.10)/0.20=0.05. After adding ClX2, [ClX2]=0.20 M, so Qc=(0.10)(0.20)/0.20=0.10. As Qc>Kc, the net reaction is backward.