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JEE Main levelSingle correct optionDifficulty 2 of 3ce024

A mixture of $N X_{2}$ , $H X_{2}$ and $NH X_{3}$ is at equilibrium: $N X_{2} (g) + 3 H X_{2} (g) 2 NH X_{3} (g)$ . The volume is suddenly halved at constant temperature. Immediately afterwards, the reaction quotient $Q_{c}$ and the direction of the net change are

A $Q_{c} = 4 K_{c}$ , backward
B $Q_{c} = K_{c} /2$ , forward
C $Q_{c} = K_{c}$ , no change
D $Q_{c} = K_{c} /4$ , forward

Answer: D

Halving the volume doubles every concentration.

Q_{c} = (2 c_{NH X_{3}})^{2} / ((2 c_{N X_{2}}) (2 c_{H X_{2}})^{3}) = 2^{2 - 4} K_{c} = K_{c} /4

. Since

Q_{c} < K_{c}

, the net change is forward.

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