JEE Main levelNumerical answerDifficulty 2 of 3cb133
According to MO theory, find the value of (bond order of OX2X+) − (bond order of OX2X2−). Give the answer to two decimal places.
Numerical answer type, tolerance 0.01.
Answer: 1.5
OX2X+ has 11 valence electrons: 8 bonding, 3 antibonding, bond order =(8−3)/2=2.5. OX2X2− has 14: 8 bonding, 6 antibonding, bond order =(8−6)/2=1. Difference =2.5−1=1.50.