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JEE Advanced levelSingle correct optionDifficulty 3 of 3cb102

The correct order of the O-N-O bond angle in $NO X_{2} X^{+}$ , $NO X_{2}$ and $NO X_{2} X^{-}$ is

A $NO X_{2} > NO X_{2} X^{+} > NO X_{2} X^{-}$
B $NO X_{2} X^{+} > NO X_{2} > NO X_{2} X^{-}$
C $NO X_{2} X^{+} > NO X_{2} X^{-} > NO X_{2}$
D $NO X_{2} X^{-} > NO X_{2} > NO X_{2} X^{+}$

Answer: B

NO X_{2} X^{+}

has no lone pair on nitrogen and is linear (

18 0^{\circ}

).

NO X_{2}

has one unpaired electron, which repels less than a lone pair (about

13 4^{\circ}

).

NO X_{2} X^{-}

has a full lone pair (about

11 5^{\circ}

).

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