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JEE Main levelSingle correct optionDifficulty 2 of 3cb093

The correct order of N-O bond length in $NO X^{+}$ , $NO$ and $NO X^{-}$ is

A $NO X^{-} < NO < NO X^{+}$
B $NO < NO X^{+} < NO X^{-}$
C $NO X^{+} < NO X^{-} < NO$
D $NO X^{+} < NO < NO X^{-}$

Answer: D

Valence electrons are 10, 11 and 12, giving MO bond orders 3, 2.5 and 2. Higher bond order gives a shorter bond, so the lengths increase from

NO X^{+}

to

NO X^{-}

.

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