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JEE Main levelSingle correct optionDifficulty 2 of 3cb092

The H-N-H angle in $NH X_{3}$ ( $10 7^{\circ}$ ) is larger than the F-N-F angle in $NF X_{3}$ ( $102. 5^{\circ}$ ) because

Anitrogen is $s p^{2}$ in $NF X_{3}$ and $s p^{3}$ in $NH X_{3}$
Bfluorine pulls the bonding electrons away from nitrogen, so bond pair-bond pair repulsion at nitrogen is lower in $NF X_{3}$
Cthere is no lone pair on nitrogen in $NF X_{3}$
Dfluorine atoms are smaller than hydrogen atoms

Answer: B

Both molecules are pyramidal and

s p^{3}

with one lone pair. In

NF X_{3}

the electronegative F draws the bonding pairs towards itself, away from N, so bond pairs repel one another less and the lone pair squeezes the angle further.

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