Aldol and intramolecular aldol products of drawn carbonyls

13 questions on Aldol and intramolecular aldol products of drawn carbonyls from the Aldehydes, Ketones and Carboxylic Acids chapter: 5 NEET level, 4 JEE Main, 4 JEE Advanced. Each one opens with its answer and solution.

• The compound shown is warmed with concentrated aqueous NaOH. Which statement is correct? NEET level, drawn structure
• The aldehyde shown is treated with dilute NaOH at low temperature. Which structure is the aldol addition product (no dehydration)? NEET level, drawn structure
• Two molecules of the ketone shown undergo base-catalysed aldol addition, and the aldol is then dehydrated (loss of one H2O only). Which structure is the final p... NEET level, drawn structure
• The aldehyde shown is warmed with an excess of propanone in dilute NaOH (1:1 condensation, one H2O lost). Which structure is the product? NEET level, drawn structure
• The diketone shown is heated with dilute NaOH. The intramolecular aldol condensation closes a ring of which size? NEET level, drawn structure
• The diketone shown is heated with dilute NaOH. Which structure is the intramolecular aldol condensation product (cyclic enone)? JEE Main level, drawn structure
• The dialdehyde shown is treated with dilute base and heated. Which structure is the intramolecular aldol condensation product? JEE Main level, drawn structure
• The aldehyde shown is mixed with ethanal in dilute NaOH. Counting only aldol addition products (beta-hydroxy aldehydes) as different constitutional isomers, and... JEE Main level, drawn structure
• The aldehyde shown is heated with concentrated NaOH. Which outcome is correct? JEE Main level, drawn structure
• The aromatic aldehyde shown is heated with excess methanal (formaldehyde) in concentrated NaOH (crossed Cannizzaro). Which statements are correct? JEE Advanced level, drawn structure
• Two equivalents of benzaldehyde react with the ketone shown in aqueous ethanolic NaOH at room temperature until both alpha carbons have condensed (all water los... JEE Advanced level, drawn structure
• The aldehyde shown undergoes self-aldol addition with dilute NaOH to give a single constitutional beta-hydroxy aldehyde. How many stereoisomers (configurational... JEE Advanced level, drawn structure
• The keto-aldehyde shown is treated with dilute NaOH and warmed. Which statements are correct? JEE Advanced level, drawn structure