Answer: A, B, D
The drawn compound is 4-chlorobenzaldehyde. Neither it nor methanal has alpha-hydrogen, so no aldol occurs. In crossed Cannizzaro the more easily hydrated, more reactive methanal is the hydride donor (oxidised to formate) and the aryl aldehyde is reduced to 4-chlorobenzyl alcohol. So statements 1, 2 and 4 are correct.