Ethanoic anhydride is treated with exactly two equivalents of methylamine, CH3NH2, in an inert solvent. The products are

N-methylethanamide and methylammonium ethanoate

N-methylethanamide and ethanoic acid

ethanamide and methyl ethanoate

N-methylethanamide and methylammonium ethanoate

N,N-dimethylethanamide and ethanoic acid

MolSynapse / Question bank / Aldehydes, Ketones and Carboxylic Acids / Carboxylic acids: acidity, preparation, derivatives, HVZ reaction

JEE Advanced levelSingle correct optionDifficulty 3 of 3co205

Ethanoic anhydride is treated with exactly two equivalents of methylamine, $CH X_{3} NH X_{2}$ , in an inert solvent. The products are

AN-methylethanamide and ethanoic acid
Bethanamide and methyl ethanoate
CN-methylethanamide and methylammonium ethanoate
DN,N-dimethylethanamide and ethanoic acid

Answer: C

One amine molecule attacks the anhydride to give

CH X_{3} CONHCH X_{3}

and ethanoic acid. The second equivalent of the basic amine neutralises the acid, giving methylammonium ethanoate. The anhydride needs two moles of amine per mole for complete conversion of one acyl group.

Practice Aldehydes, Ketones and Carboxylic Acids More on Carboxylic acids: acidity, preparation, derivatives, HVZ reaction

Previous questionNext question

Ethanoic anhydride is treated with exactly two equivalents of methylamine, CHX3​NHX2​, in an inert solvent. The products are

Answer: C

More questions on Carboxylic acids: acidity, preparation, derivatives, HVZ reaction

Ethanoic anhydride is treated with exactly two equivalents of methylamine, $CH X_{3} NH X_{2}$ , in an inert solvent. The products are