Ethanoic acid is treated with excess $\mathrm{LiAlH}{}_4$ in dry ether, followed by dilute acid work-up. The organic product is

$\mathrm{LiAlH}{}_4$ reduces a carboxylic acid all the way to the primary alcohol with the same carbon skeleton, $\mathrm{CH}{}_3\mathrm{COOH}\to \mathrm{CH}{}_3\mathrm{CH}{}_2\mathrm{OH}$. The aldehyde is not isolated because it is reduced faster than the acid.