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NEET levelSingle correct optionDifficulty 1 of 3co169

Sodium ethanoate is heated strongly with soda lime ( $NaOH$ + $CaO$ ). The hydrocarbon formed is

A $C X_{2} H X_{6}$
B $CH X_{4}$
C $C X_{2} H X_{4}$
D $C X_{3} H X_{8}$

Answer: B

Soda lime decarboxylation replaces

COONa

by H:

CH X_{3} COONa + NaOH CH X_{4} + Na X_{2} CO X_{3}

. One carbon is lost as carbonate, so the product is methane.

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