Answer: D
Bimolecular reduction gives P = 2,3-dimethylbutane-2,3-diol. Acid causes methyl migration to give Q = (CHX3)X3CCOCHX3, 3,3-dimethylbutan-2-one. The haloform reaction removes the CHX3 as CHClX3, so R = (CHX3)X3CCOOH, 2,2-dimethylpropanoic acid.