Which diesters give a five- or six-membered cyclic beta-keto ester as the main product when treated with one equivalent of NaOEt in ethanol (Dieckmann condensation)? (One or more answers)

The enolate carbon C2 attacks the ester carbonyl at the other end, forming a ring that contains all carbons from C2 to the terminal carbonyl carbon. Butanedioate and pentanedioate would give rings of 3 and 4, which are strained. Hexanedioate gives 5 and heptanedioate gives 6.