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JEE Advanced levelOne or more correct optionsDifficulty 3 of 3co051

Butan-2-one is allowed to react with various reagents. The correct pairs of reagent and product are

A $HCN$ with trace $OH X^{-}$ : 2-hydroxy-2-methylbutanenitrile
B $(C X_{6} H X_{5}) X_{3} P = CH X_{2}$ : 2-methylbut-2-ene
C $CH X_{3} MgBr$ then $H X_{3} O X^{+}$ : 2-methylbutan-2-ol
D $NH X_{2} OH$ : butan-2-one oxime

Answer: A, C, D

The cyanohydrin, oxime and tertiary alcohol are formed as stated. The Wittig reagent converts

C = O

to

C = CH X_{2}

, giving 2-methylbut-1-ene, not the 2-ene.

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