Benzene (15.6 g) is acylated with excess ethanoyl chloride and anhydrous $AlCl X_{3}$ to give acetophenone in 70% yield. All of the acetophenone obtained is then treated with excess $I X_{2}$ / $NaOH$ , giving $CHI X_{3}$ in 80% yield. Calculate the mass of $CHI X_{3}$ formed in grams to one decimal place. (C 12, H 1, O 16, I 127.)

Numerical answer type, answer in g, tolerance 0.05.

Answer: 44.1 g

Moles of benzene

= 15.6/78 = 0.20

. Acetophenone

= 0.20 \times 0.70 = 0.140

mol.

C X_{6} H X_{5} COCH X_{3} CHI X_{3}

is one to one, so moles of

CHI X_{3}

= 0.140 \times 0.80 = 0.1120

mol. Mass

= 0.1120 \times 394 = 44.13

g, i.e. 44.1 g.