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NEET levelSingle correct optionDifficulty 1 of 3bm235

The cyclic sugar shown is

  1. Aalpha-D-glucopyranose
  2. Bbeta-D-glucopyranose
  3. Calpha-D-glucofuranose
  4. Dalpha-D-galactopyranose

Answer: A

The ring has six members (five carbons and one oxygen), so it is a pyranose, and the substituents match D-glucose. The anomeric OH is on the opposite face of the ring from the CH2OH group at C-5 (axial in the chair), which is the alpha anomer; its CIP label at C-1 is S (beta is R). The sugar is alpha-D-glucopyranose.
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