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The zwitterionic form of alanine is

A $H X_{3} N X^{+} - CH (CH X_{3}) - COO X^{-}$
B $H X_{2} N - CH (CH X_{3}) - COOH$
C $H X_{3} N X^{+} - CH (CH X_{3}) - COOH$
D $H X_{2} N - CH (CH X_{3}) - COO X^{-}$

Answer: A

In the zwitterion the carboxyl proton has moved to the amino group, giving -NH3+ and -COO- in the same molecule with zero net charge.

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