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JEE Main levelNumerical answerDifficulty 2 of 3bn184

Magnetite is $Fe X_{3} O X_{4}$ , with O = $- 2$ . Find the AVERAGE oxidation number of Fe in $Fe X_{3} O X_{4}$ . Give the answer to two decimals.

Numerical answer type, tolerance 0.01.

Answer: 2.67

Average Fe:

3 x + 4 (- 2) = 0

, so

x = 8/3 = 2.6667

, i.e. 2.67.

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