JEE Main levelSingle correct optionDifficulty 2 of 3bn181
Match the compound (Column I) with the oxidation number of oxygen in it (Column II). Use O = −1 in peroxide, −1/2 in superoxide and F = −1.
Column I: P NaX2OX2; Q KOX2; R OFX2; S NaX2O.
Column II: 1 −2; 2 −1; 3 +2; 4 −1/2.
AP-2, Q-4, R-3, S-1
BP-4, Q-2, R-3, S-1
CP-2, Q-4, R-1, S-3
DP-1, Q-3, R-2, S-4
Answer: A
NaX2OX2 is a peroxide: O = −1 (P-2). KOX2 is a superoxide: O = −1/2 (Q-4). In OFX2, F = −1 so x+2(−1)=0 gives O = +2 (R-3). In NaX2O O = −2 (S-1).