JEE Advanced levelSingle correct optionDifficulty 3 of 3bn149
Arrange the following anions by INCREASING oxidation number of the central atom: (i) hypochlorite, (ii) nitrite, (iii) chlorate, (iv) sulfate, (v) permanganate.
A(i) < (ii) < (iii) < (iv) < (v)
B(ii) < (i) < (iii) < (iv) < (v)
C(i) < (ii) < (iii) < (v) < (iv)
D(i) < (iii) < (ii) < (iv) < (v)
Answer: A
Hypochlorite ClOX−: Cl +1. Nitrite NOX2X−: N +3. Chlorate ClOX3X−: Cl +5. Sulfate: S +6. Permanganate: Mn +7. So (i) < (ii) < (iii) < (iv) < (v).