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JEE Advanced levelSingle correct optionDifficulty 3 of 3bn077

Prussian blue is iron(III) hexacyanoferrate(II). Which formula is correct?

A $Fe X_{3} [Fe (CN) X_{6}] X_{2}$
B $Fe X_{3} [Fe (CN) X_{6}] X_{4}$
C $Fe X_{4} [Fe (CN) X_{6}] X_{3}$
D $Fe [Fe (CN) X_{6}]$

Answer: C

Hexacyanoferrate(II) is

[Fe (CN) X_{6}] X^{4 -}

and iron(III) is

Fe X^{3 +}

.

3 \times 4 = 4 \times 3 = 12

, so four Fe(III) and three complex ions:

Fe X_{4} [Fe (CN) X_{6}] X_{3}

.

Fe X_{3} [Fe (CN) X_{6}] X_{2}

is the iron(II) hexacyanoferrate(III).

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