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JEE Advanced levelOne or more correct optionsDifficulty 3 of 3bn045

Open-chain glucose is (six carbons). Use the usual electronegativity rule (bond to O counts per bond including double-bond counting, bond to H counts , C-C bonds count ). Select the correct statements. (Choose among the options below.)

  1. AThe aldehyde carbon has oxidation number
  2. BEvery one of the six carbon atoms has oxidation number
  3. CThe average oxidation number of carbon in glucose is
  4. DThe terminal carbon has oxidation number

Answer: A, C, D

CHO carbon: C=O gives , C-H gives , so . Each of the four CHOH carbons: one O () and one H (), so . The CH2OH carbon: one O () and two H (), so . Sum , so the average over six carbons is . The statement that all six carbons are is wrong.
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