JEE Main levelOne or more correct optionsDifficulty 2 of 3bn033
In which of the following is the named atom in the +6 oxidation state? (HX2SOX5 contains one peroxo link, so two of its O atoms are −1 and the other three are −2; in NaX2SX2OX3 use the average over both S atoms.)
ACr in KX2CrOX4
BS in HX2SOX5
CMn in KX2MnOX4
DS in NaX2SX2OX3
Answer: A, B, C
KX2CrOX4: 2+x−8=0 gives Cr +6. KX2MnOX4: Mn +6. HX2SOX5: 2+x+2(−1)+3(−2)=0 gives S +6. NaX2SX2OX3: 2+2x−6=0 gives an average of S +2.