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Basic Inorganic Nomenclature and Oxidation Number
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Oxidation number determination including fractional and unusual cases
NEET level
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Difficulty 1 of 3
bn005
What is the oxidation number of sulfur in the sulfite ion,
SO
X
3
X
2
−
(O is
−
2
)?
A
+
3
B
+
6
C
+
4
D
+
2
Answer: C
Each O is
−
2
and the ion has charge
−
2
:
x
+
3
(
−
2
)
=
−
2
, so
x
=
+
4
.
Practice Basic Inorganic Nomenclature and Oxidation Number
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