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Bohr model: energy, radius, velocity, ionisation energy
JEE Advanced level
Single correct option
Difficulty 3 of 3
as095
In the Bohr model, the frequency of revolution of the electron in the
n
=
2
orbit of
He
X
+
divided by that in the
n
=
1
orbit of
H
is
A
2
1
B
2
C
4
1
D
4
Answer: A
Frequency
f
=
v
/2
π
r
∝
(
Z
/
n
)
/
(
n
2
/
Z
)
=
Z
2
/
n
3
. For
He
X
+
,
n
=
2
:
4/8
=
1/2
. For H,
n
=
1
:
1
. The ratio is
1/2
.
Practice Atomic Structure
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