Use a_0 = 0.529 AA and take the speed in the first Bohr orbit of hydrogen as 2.19x10^6 m s^-1. Calculate the time period of revolution of the electron in the n=3 orbit, in units of 10^-15 s (two decimals).

JEE Main levelNumerical answerDifficulty 2 of 3as083

Use $a_{0} = 0.529 \overset{˚}{A}$ and take the speed in the first Bohr orbit of hydrogen as $2.19 \times 1 0^{6} m s^{- 1}$ . Calculate the time period of revolution of the electron in the $n = 3$ orbit, in units of $1 0^{- 15} s$ (two decimals).

Numerical answer type, answer in 1e-15 s, tolerance 0.02.

r_{3} = 9 a_{0} = 4.761 e - 10 m

and

v_{3} = 2.19 \times 1 0^{6} /3 = 7.300 e + 05 m s^{- 1}

T = 2 π r_{3} / v_{3} = 4.10 \times 1 0^{- 15} s