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JEE Main levelSingle correct optionDifficulty 2 of 3as067

Take $E_{1} = - 13.6 eV$ for hydrogen. The energy of an electron in the $n = 2$ level of $Li X^{2 +}$ is

A $- 30.6 eV$
B $- 10.2 eV$
C $- 20.4 eV$
D $- 122.4 eV$

Answer: A

E_{n} = - 13.6 Z^{2} / n^{2}

. With

Z = 3

,

n = 2

:

E_{2} = - 13.6 \times 9/4 = - 30.6 eV

.

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