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NEET levelSingle correct optionDifficulty 1 of 3as059

Take $E_{1} = - 13.6 eV$ for hydrogen. The ionisation energy of the ground-state $He X^{+}$ ion is

A $13.6 eV$
B $54.4 eV$
C $27.2 eV$
D $122.4 eV$

Answer: B

E_{n} = - 13.6 Z^{2} / n^{2} eV

. For

He X^{+}

,

Z = 2

,

n = 1

, so

∣ E_{1} ∣ = 13.6 \times 4 = 54.4 eV

, which is the ionisation energy.

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