Answer: A, B, C
The diol is 1,1'-bi(cyclopentyl)-1,1'-diol (CX10HX18OX2). Loss of water and migration of a ring CHX2 expands one ring to six members and gives spiro[4.5]decan-6-one, CX10HX16O, whose spiro carbon is quaternary. No hydrogen is available on either carbinol carbon, so no aldehyde forms and D is wrong.