Answer: A, B, C
The diol is pinacol; the product is pinacolone, (CHX3)X3C−CO−CHX3. It is formed through a tertiary cation followed by a methyl shift, so statements A and B hold. Pinacolone is a methyl ketone, so it gives iodoform with IX2/NaOH (C). It is a ketone, not an aldehyde, so D is wrong.