JEE Main levelSingle correct optionDifficulty 2 of 3ap208
Methyl isopropyl ether, CHX3−O−CH(CHX3)X2, is treated with one equivalent of HI and warmed. The products are
A(CHX3)X2CHI and methanol
BCHX3I and (CHX3)X2CHI
Cpropene and methanol
DCHX3I and propan-2-ol
Answer: D
With primary or secondary alkyl groups the cleavage is SN2: iodide attacks the less hindered carbon of the protonated ether, here the methyl group. The products are CHX3I and (CHX3)X2CHOH.