Answer: D
The Lucas delay of about five minutes marks a secondary alcohol, and the iodoform test marks CHX3CH(OH)−R. So Y is butan-2-ol, CHX3CH(OH)CHX2CHX3. Reduction of the ketone CHX3COCHX2CHX3, butan-2-one (C4H8O), gives Y. Butanal would give a primary alcohol and 2-methylpropanal gives a primary alcohol too, while but-3-en-1-ol is not reduced to a secondary alcohol.