Answer: C
The diol is symmetrical, so ionisation of either OH gives the same type of tertiary cation. Of the two groups on the neighbouring carbinol carbon, ethyl and methyl, ethyl migrates better. The cationic carbon becomes C(CHX3)(Et)X2 and the other carbon becomes C(=O)CHX3, giving CHX3CO−C(CHX3)(CHX2CHX3)X2.