Answer: D
Loss of the hydroxyl on C-1 gives a diarylcarbenium ion that is far more stable than the tertiary alkyl cation at C-2, and the 4-methoxy group stabilises it further. The only groups on C-2 that can migrate are the two methyls, so one methyl moves to C-1. C-2 becomes C(=O)CHX3 and C-1 becomes C(CHX3)(Ar)(Ph), giving 3-(4-methoxyphenyl)-3-phenylbutan-2-one.