Answer: D
Ionisation gives the secondary cation CHX3−CHX+−C(CHX3)X3. A 1,2-methyl shift gives the tertiary cation (CHX3)X2CH−CX+(CHX3)X2. Loss of the proton from the isopropyl CH gives the tetrasubstituted alkene 2,3-dimethylbut-2-ene (Saytzeff), the major product.