Answer: C
Protonation and loss of water give the secondary cation (CHX3)X2CH−CH(+)−CHX3. A 1,2-hydride shift gives the tertiary cation (CHX3)X2C(+)−CHX2−CHX3. Loss of a proton by the Saytzeff rule gives the most substituted alkene, 2-methylbut-2-ene.