JEE Advanced levelOne or more correct optionsDifficulty 3 of 3td209
For one mole of a monatomic ideal gas, the molar heat capacity C along a reversible path PVn=constant is C=CV+R/(1−n). Select all correct statements.
AC→∞ for the isothermal path
BC=0 for the reversible adiabatic path
CC=611R along the path P∝V2
DC is negative along the path PV2=constant
Answer: A, B, C
Isothermal corresponds to n=1, so R/(1−n) diverges. Adiabatic has n=5/3: C=1.5R+R/(1−5/3)=1.5R−1.5R=0. For P∝V2, n=−2 and C=1.5R+R/3=11R/6. For n=2, C=1.5R−R=0.5R>0, so the last statement is false.