For melting of ice, Delta H_fus = 6010 J mol^-1 and the melting point is 273 K (assume Delta H and Delta S constant). The value of Delta G for melting at 263 K is nearest to

+220 J mol^-1 (melting is non-spontaneous)

-220 J mol^-1 (melting is spontaneous)

+220 J mol^-1 (melting is non-spontaneous)

+6010 J mol^-1 (melting is non-spontaneous)

JEE Main levelSingle correct optionDifficulty 2 of 3td197

For melting of ice, $Δ H_{fus} = 6010 J mo l^{- 1}$ and the melting point is $273 K$ (assume $Δ H$ and $Δ S$ constant). The value of $Δ G$ for melting at $263 K$ is nearest to

Δ S_{f u s} = 6010/273 = 22.015 J mo l^{- 1} K^{- 1}

. Then

Δ G = Δ H - T Δ S = 6010 - 263 \times 22.015 = 220.1 J mo l^{- 1}

. It is positive, so ice does not melt at

263 K