Two moles of an ideal diatomic gas are heated by $50 K$ , once at constant pressure and once at constant volume. Taking $R = 8.314 J mo l^{- 1} K^{- 1}$ , find the difference $q_{P} - q_{V}$ in J (nearest integer).

Numerical answer type, answer in J, tolerance 1.

Answer: 831 J

q_{P} - q_{V} = n (C_{P} - C_{V}) Δ T = n R Δ T = 2 \times 8.314 \times 50 = 831.4 J

, about 831 J. The result does not depend on the atomicity.