JEE Advanced levelSingle correct optionDifficulty 3 of 3td154
For a salt MX(s) the lattice enthalpy (energy needed to separate the solid into gaseous ions) is +758kJmol−1, and the hydration enthalpies of the gaseous ions are −406 for MX+ and −364kJmol−1 for XX−. The enthalpy of solution of MX and the temperature change on dissolving it in water are
A+12kJmol−1; the solution warms
B−12kJmol−1; the solution cools
C−12kJmol−1; the solution warms
D−1528kJmol−1; the solution warms
Answer: C
ΔsolH=ΔlatticeH+ΔhydH(MX+)+ΔhydH(XX−)=758−406−364=−12kJmol−1. A negative value means heat is released, so the solution warms. +12 results from sign confusion, and −1528 from subtracting the lattice enthalpy.